CBSE Class 12 Physics 2023 Delhi Set 2 Paper

Question : 3 of 11

Marks: +1, -0

Figure shows a plot of stopping potential

( {\V}_0)

versus

\;{1}/{λ}

, is the wavelength of the radiation causing photoelectric emission from a surface. The slope of the line is equal to

Solution:

From Einstein's equation,

{\e } V_0\;= {\hv}- {\h} v_0

or,

V_0\;=\;{h v}/{e}-\;{h v_0}/{e} \;\; [ ∵ v=\;{h}/{c}]

or,

V_0\;=\;{h c}/{λ e}-\;{h c}/{λ_0 e}

So, the slope of

V_0

vs.

1 \/ λ

graph is

h c \/ e

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