Choose the correct option related to wavelengths ( \lambda ) of different parts of electromagnetic spectrum.

Correct Answer is : λradio waves >λmicro waves >λvisible >λx-rays

\lambda_{\text{x-rays }}< \lambda_{\text{micro waves }}< \lambda_{\text{radio waves }}< \lambda_{\text{visible }}

\lambda_{\text{visible }}>\lambda_{x \text{-rays }}>\lambda_{\text{Tadio waves }}>\lambda_{\text{micro waves }}

\lambda_{\text{radio waves }}>\lambda_{\text{micro waves }}>\lambda_{\text{visible }}>\lambda_{x \text{-rays }}

\lambda_{\text{visible }}< \lambda_{\text{micro waves }}< \lambda_{\text{radio waves }}< \lambda_{\text{x-rays }}

CBSE Class 12 Physics 2023 Delhi Set 2 Paper - Question 2

Question : 2 of 11

Marks: +1, -0

Choose the correct option related to wavelengths
(

λ

) of different parts of electromagnetic spectrum.

$λ_{\;\text "x-rays "\;}< λ_{\;\text "micro waves "\;}< λ_{\;\text "radio waves "\;}< λ_{\;\text "visible "\;}$
$λ_{\;\text "visible "\;}>λ_{x \;\text "-rays "\;}>λ_{\;\text "Tadio waves "\;}>λ_{\;\text "micro waves "\;}$
$λ_{\;\text "radio waves "\;}>λ_{\;\text "micro waves "\;}>λ_{\;\text "visible "\;}>λ_{x \;\text "-rays "\;}$
$λ_{\;\text "visible "\;}< λ_{\;\text "micro waves "\;}< λ_{\;\text "radio waves "\;}< λ_{\;\text "x-rays "\;}$

Solution:

Wavelength of radio wave

>0.1 {\m}

Wavelength of microwave:

1 {\mm}-0.1 {\m}

Wavelength of visible light:

400 {\nm}-700 {\nm}

Wavelength of X-rays:

10^{-3} {\nm}-1 {\nm}

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