CBSE Class 12 Math 2022 Term I Solved Paper

© examsiri.com
Question : 13 of 50
 
Marks: +1, -0
If Cij denotes the cofactor of element Pij of the matrix P=[1−1202−3324], then the value of C31⋅C23 is
Solution:
Explanation:
Here,
C31=(−1)3+1|−122−3|=3−4=−1
C23=(−1)2+3|1−132|=−(2+3)=−5
and
C23=(−1)2+3|1−132|=−(2+3)=−5
Thus, C31⋅C23=(−1)(−5)=5
© examsiri.com
Go to Question: