CBSE Class 12 Math 2022 Term I Solved Paper

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Question : 12 of 50
 
Marks: +1, -0
The function f(x)={e3x−e−5xx if x≠0k if x=0. is continuous at x=0 for the value of k, as
Solution:
Explanation: Since, f(x) is continuous at x=0, then
LHL=RHL=f(0) or LHL=RHL=k
Now,
LHL=limh→0e3(0−h)−e−5(0−h)0−h
=limh→0e−3h−e5h−h
=limh→0(e−3h−1−h)+limh→0(e5h−1h)
=3limh→0(e−3h−1−3h)+5limh→0(e5h−15h)
=3×1+5×1=8
Thus, k=8.
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