CBSE Class 12 Math 2020 Delhi Set 2 Solved Paper

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Question : 2 of 11
 
Marks: +1, -0
∫4x3xdx equals
Solution:
Let,
I=∫4x3xdx
⇒I=∫12xdx
⇒I=12xlog12+C
[∵∫axdx=axlogx+C]
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