If \left[\begin{array}{cc}x & 1]\end{array}\left[\begin{array}{cc}1 & 0 \ -2 & 0]\end{array}=0, then x equals

CBSE Class 12 Math 2020 Delhi Set 2 Solved Paper - Question 1

Note : Except for the following questions, all the remaining questions have been asked in the previous sets.

Question : 1 of 11

Marks: +1, -0

{[\table x , 1]}{[\table 1 , 0 ; -2 , 0]}=0

, then

x

equals

Solution:

\;{{[\table x , 1]}{[\table 1 , 0 ; -2 , 0]}}\;=0

\;

⇒\;{{[\table x-2 , 0]}}\;={[\table 0 , 0]}

⇒ x-2\;=0

⇒\;x\;=2

\; ∴ \;\text " Option (d) is correct. "\;\;

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