CBSE Class 12 Chemistry 2022 Term 2 Delhi Set 3

Question : 3 of 12

Marks: +1, -0

An Organic compound (A) with molecular formula

{\C}_3 {\H}_7 {\NO}

on heating with

{\Br}_2

and

{\KOH}

forms a compound (B). Compound (B) on heating with

{\CHCl}_3

and alcoholic

{\KOH}

produces a foul smelling compound

( {\C})

and on reacting with

{\C}_6 {\H}_5 {\SO}_2 {\Cl}

forms a compound (D) which is soluble in alkali. Write the structure of (A), (B), (C) and (D).

Solution:

{ {\CH}_3 {\CH}_2 {\CONH}_2}↙{(\A)}+ {\Br}_2+ {\KOH} →{ {\CH}_3 {\CH}_2 {\NH}_2 }↙{(\B)}

{{\CH}_3 {\CH}_2 {\NH}_2}↙{(\B)}+ {\CHCl}_3+ {\KOH} → {{\CH}_3 {\CH}_2 {\NC} }↙{(\C)}

+ {\KCl}+ {\H}_2 {\O}

\;A=\;\text " Propanaimde "\;

\;B=\;\text " Ethyl amine "\; (1^{∘} \;\text " amine "\;)

\;C=\;\text " Ethyl isocyanide "\;

\;D=\;\text " N-ethyl benzene sulphonamide "\;

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