CBSE Class 12 Chemistry 2022 Term 2 Delhi Set 2

Question : 4 of 4

Marks: +1, -0

A primary amine '

A

{\C}_2 {\H}_7 {\N}

reacts with alkyl halide

(C_2 H_5 1)

to give secondary amine '

B

'. '

B

' reacts with

{\C}_6 {\H}_5 {\SO}_2 {\Cl}

to give a solid '

{\C}

' which is insoluble in alkali. Identify 'A', 'B', 'C' and write all the chemical reactions involved.

Solution:

\; {{\CH}_3 {\CH}_2 {\NH}_2}↙{1^{∘} \Amine (\A)}+ {{\CH}_3 {\CH}_2 {\I}}↙{\Ethyl \iodide} → { {\CH}_3 {\CH}_2 {\NHCH}_3 {\CH}_2 }↙{ 2^{∘} \Amine(\B) }

\;+{ {\C}_6 {\H}_5 {\SO}_2 {\Cl}}↙{ {\N}, {\N} -\diethyl \benzene } → {{\C}_6 {\H}_5 {\SO}_2 {\N}_2 ( {\C}_2 {\H}_5)}↙{ \sulphonamide (C)}

\;A=\;\text " Ethyl amine "\;

\;B=\;\text " Diethyl amine "\;

\;C=N, N \;\text "-diethyl benzene sulphonamide. "\;

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