Xavier Aptitude Test 2022 Paper

$\left(1,6,7\right),\left(1,6,9\right),\left(6,7,9\right),\left(1,7,9\right)$
But the cases $6,7,9$ fails because if he answered all three of them correctly then he must have answered 1 wrongly but since if 1 is answered wrong then all of $1,6,7,9$ are answered correctly by Simarjeet when Simarjeet can answer actually a total of 3 questions only correctly hence this case fails.
Similarly if considered the cases $\left(1,6,7\right)$ and $\left(1,6,9\right)$ as the questions which were answered correctly. The cases fail because if they are answered correctly we cannot possibly have Pavan answering 5 questions correctly.
Hence the only possibility is he must have answered the questions :
$\left(1,7,9\right)$ correctly.
Hence the correct answers are :

Now drawing the table based on the answers marked by them

Simarjeet must have answered 1 question of the Q 2, Q 4, and Q 6 correctly. Qadir must have answered the remaining two of them correctly.
If Simarjeet answered Q 4 correctly and Q 2, Q 6 wrong the answers for Q 2, Q 4 and Q 6 will be: B, B, and D
But if Q 2 and Q 4 are answered as B then Om must have scored 3 marks instead of 2 and hence the case fails.
If Simarjeet answered Q 6 correctly and Q 2, Q 4 wrong the answers for Q 2, Q 4 and Q6 will be: A, C, and C.
But Pavan cannot score 5 marks.
Hence Simarjeet must have answered Q 2 correctly and answers for Q 2, Q 4, and Q6 will be :
(B, C, D).

Q 4 was answered wrong by 5 members