Xavier Aptitude Test 2021 Paper

Question : 1 of 100

Marks: +1, -0

If $\log_4 m + \log_4 n= \log_2(m+n)$ where $m$ and $n$ are positive real numbers, then which of the following must be true?

Solution:

\log_4 mn = \log_2 (m + n)

√{mn} = (m+n)

Squarring on both sides

m^2 + n^2 + mn = 0

Since

m

n

are positive real numbers, no value of

m

and

n

satisfy the above equations.

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