Xavier Aptitude Test 2020 Paper

Question : 50 of 100

Marks: +1, -0

Two friends, Ram and Shyam, start at the same point, at the same time. Ram travels straight north at a speed of $10\km \per \hr$ , while Shyam travels straight east at twice the speed of Ram. After $15 \minutes$ , Shyam messages Ram that he is just passing by a large telephone tower and after another $15 \minutes$ Ram messages Shyam that he is just passing by an old banyan tree. After some more time has elapsed, Ram and Shyam stop. They stop at the same point of time. If the straight-line distance between Ram and Shyam now is $50 \km$ , how far is Shyam from the banyan tree (in km)? (Assume that Ram and Shyam travel on a flat surface.)

$45$
$20√5 -5$
$20 √5 + 5$
$115/3$
5√21

Validate

Solution:

2500 = (5 + 10t)^2 + (10 +20t)^2 → (1 + 2t)^2 =20

\AB^2 = 25 + 100 (1+ 2t)^2 → \AB= 45\km

Go to Question:

Prev Question

Next Question