Xavier Aptitude Test 2015 Paper

(c) LCM of 3, 4, 5, 6 = 60
Hence , the number will be 60k + 2, where k is an integer.
The number is divisible by 11.
Now, (60k + 2)/ 11 can be rearranged as
55k/11 + (5k + 2) /11
The number is divisible by 11. So,5k + 2 = 11 i.e. k = 4
As k is an integer, the next values of k is 4 + 11 = 15, 15
+ 11 = 26, 26 + 11 = 37, 37 + 11 = 48 and 48 + 11= 59 (for
6th smallest number)
Hence, 6th number of the series = 60 × 59 + 2 = 3542.