Xavier Aptitude Test 2015 Paper

Question : 63 of 113

Marks: +1, -0

If a, b, c, and d are four different positive integers selected from 1 to 25, then the highest possible value of ((a + b) + (c + d)) /((a + b) + (c – d)) would be :

47
49
51
96
None of the above

Validate

Solution:

For highest value of {(a + b) + (c + d)} / {(a + b) +
(c – d)}, the denominator {(a + b) + (c – d)} should be 1⁄2 but the numerator {(a + b) + (c + d)} should be maximum since a, b, c and d are four different positive integers from 1 to 25, therefore
a + b + c = 26 and d = 1
Hence highest possible value of

{(a + b) + (c + d)}/{(a + b)+ (c + d)}

{26 + 25}/{26 - 25}

= 51

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