Xavier Aptitude Test 2013 Paper

Question : 75 of 121

Marks: +1, -0

The radius of a circle with centre O is

√50

cm. A and C two points on the circle, and B is a point inside the circle. The length of AB is 6 cm, and the length of BC is 2 cm. The angle ABC is a right angle. Find the square of the distance OB.

Validate

Solution:

(b)

In any triangle, the difference of any 2 sides < 3rd side Consider ΔOBC
Side BC = 2
∴ Side OB =

√50

– 2
Side OB = 7.07 – 2 = 5.07
OB > 5.07
squaring on both sides
OB

^{2}

> (5.07)

^{2}

i.e. OB

^{2}

= 25

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