Xavier Aptitude Test 2013 Paper

Question : 66 of 121

Marks: +1, -0

p and q are positive numbers such that p q = qp , and q = 9p. The value of p is

Solution:

(d) Given,

p^{9}=q^{p}

\ (p^{9}\ )^{1 / p}= (q^{p}\ )^{1 / p}

p^{q / p}=q

\ {9 p}/{p}=q \ [\∵ q=9 p]

\ \ \ p^{9}=q

.........(1)
Also

p=\ {q}/{9}

.......... (2)
Dividing equation (1) by (2), we get

p^{8}=9

\ 8 √{9}

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