Xavier Aptitude Test 2011 Paper

SECTION - II : DATA INTERPREATION AND QUANTITATIVE ABILITY

DIRECTIONS (Qs. 25 and 26) : Answer the questions based on the following information
A man standing on a boat south of a light house observes his shadow to be 24 meters long, as measured at the sea level. On sailing 300 meters eastwards, he finds his shadow as 30 meters long, measured in a similar manner. The height of the man is 6 meters above sea level.

Question : 25 of 101

Marks: +1, -0

The height of the light house above the sea level is:

90 meters
94 meters
96 meters
100 meters
106 meters

Validate

Solution:

(e)

{KL} \→

light house initally

\ {BA} →

Man and

\mathrm{BC}

is his shadow
and affermoving 300

\ {m}

east whose shadow is now EF and his new position is

\ {DE}

\ {AB}=\ {DE}=6

(height of man will same)
From similar triangle, KLC and ABC

{\ {KL}}/{\ {AB}}=\ {\ {LC}}/{\ {BC}}

and

\Δ {KLF} \≈\Δ{EDF}

\∴{\ {KL}}/{\ {DE}}=\ {L F}/{\ {EF}}

{ {LC}}/{\ {BC}}=\ { {LF}}/{\ {EF}}

\⇒{LC} ×{EF}=\ {LF} \×{BC}

\⇒ {\ {BC}}/{\ {EF}}=\ {\ {LC}}/{\ {LF}}= {24}/{30}=\ {4}/{5}

LC is 4 part

≡

LF 5 part
then

L B

is 4 part

\≡

LE is 5 part.
As,

L B=400, L E=500

K L= {L C}/{B C} \× A B=\ {424}/{24} \× 6=106 m

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