216^{2\/ 3} \div (\frac{p^{2}}{9}) ^{−3\/ 2} = 2^{x}3^{y}p^{z}, the values of x, y, z are

Correct Answer is : x = 2, y = -1, z = 3

WBPSC 2020 Solved Paper

Question : 107 of 200

Marks: +1, -0

216^{2\/ 3} ÷ (\;{p^{2}}/{9}) ^{−3\/ 2} = 2^{x}3^{y}p^{z},

the values of x, y, z are

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