If 1^{2} + 2^{2} + 3^{2} + ... + n^{2} = \frac{n(n + 1)(2n + 1)}{6}, find the value of 5^{2} + 6^{2} + 7^{2} + .... + 10^{2}.

WBPSC 2019 Solved Paper

Question : 143 of 200

Marks: +1, -0

1^{2} + 2^{2} + 3^{2} + ... + n^{2} = \;{n(n\;+\;1)(2n\;+\;1)}/{6},

find the value of

5^{2} + 6^{2} + 7^{2} + .... + 10^{2}.

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