Three point charges {\q},-2 {\q} and q are placed along x axis at x=-a, 0 and a respectively. As {\a} \rightarrow 0 and {\q} \rightarrow \infty while {\qa}^2= {\Q} remains finite, the electric field at a point P , at a distance x(x ≫ a) from x=0 is { {\E}}^{\to}=\frac{\alpha {\Q}}{4 \pi E_0 x^\beta} \stackrel{\^}{i}. Then

WBJEE 2024 Physics & Chemistry Paper

Question : 68 of 80

Marks: +1, -0

Three point charges q,−2q and q are placed along x axis at x=−a,0 and a respectively. As a⟶0 and q⟶∞ while qa2=Q remains finite, the electric field at a point P , at a distance x(x≫a) from x=0 is

→

=‌

αQ

4πE0xβ

. Then

‌α=β
‌α=2β
‌α=‌
2
3
β
‌2α=3β

Validate

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