If \left[\begin{array}{cc}2 & 1 \ 3 & 2]\end{array} \cdot A \cdot\left[\begin{array}{cc}-3 & 2 \ 5 & -3]\end{array}=\left[\begin{array}{cc}1 & 0 \ 0 & 1]\end{array}, then A=

\left[\begin{array}{cc}1 & 1 \ 1 & 0]\end{array}

\left[\begin{array}{cc}1 & 1 \ 0 & 1]\end{array}

\left[\begin{array}{cc}1 & 0 \ 1 & 1]\end{array}

\left[\begin{array}{cc}0 & 1 \ 1 & 1]\end{array}

WBJEE 2024 Math Paper

Question : 24 of 75

Marks: +1, -0

If [

2	1
3	2

]⋅A⋅[

−3	2
5	−3

]=[

1	0
0	1

], then A=

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