Let {\f}: \mathbb{R} \rightarrow \mathbb{R} be given by {\f}(x)={|x^2-1| }, then

Correct Answer is : f has a local minima at x=±1 and a local maxima at x=0

f has a local minima at x= \pm 1 but no local maxima

f has a local maxima at x=0, but no local minima

f has a local minima at x= \pm 1 and a local maxima at x=0

f has neither any local maxima nor any local minima

WBJEE 2024 Math Paper

Question : 10 of 75

Marks: +1, -0

Let f:ℝ⟶ℝ be given by f(x)=|x2−1|, then

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x2−1	x2≥1
1−x2	x2<1