Let f(x)={\\begin{array}{ccc}x+1 & & -1 \leq x \leq 0 \ -x & & 0&lt\ x \leq 1\end{array}.

Correct Answer is : f(x) is discontinuous in [−1,1] but still has the maximum and minimum value.

f(x) is discontinuous in [-1,1] and so has no maximum value or minimum value in [-1,1]

f(x) is continuous in [-1,1] and so has maximum value and minimum value.

f(x) is discontinuous in [-1,1] but still has the maximum and minimum value.

f(x) is bounded in [-1,1] and does not attain maximum or minimum value.

WBJEE 2023 Math Solved Paper

Question : 14 of 75

Marks: +1, -0

Let f(x)={

x+1	‌	−1≤x≤0
−x	‌	0<x≤1

f(x) is discontinuous in [−1,1] and so has no maximum value or minimum value in [−1,1]
f(x) is continuous in [−1,1] and so has maximum value and minimum value.
f(x) is discontinuous in [−1,1] but still has the maximum and minimum value.
f(x) is bounded in [−1,1] and does not attain maximum or minimum value.

Go to Question:

Prev Question

Next Question