For x \\inR, x \\neq-1, if (1+x)^{2016}+x(1+x)^{2015}+x^{2}(1+x)^{2014} +\......+x^{2016}=\\sum_{i=0} ^{2016} a_{1} \.x^{i}, then a_{17} is equal to

Correct Answer is : 2017!17!2000!

WBJEE 2021 Math Solved Paper

CATEGORY - I (Q:1 to Q50)

Carry 1 mark each and only one option is correct. In case of incorrect answer or any combination of more than one answer, ¼ mark will be deducted.

Question : 16 of 75

Marks: +1, -0

For x∈R,x≠−1, if (1+x)2016+x(1+x)2015+x2(1+x)2014 +......+x2016=

2016

∑

i=0

a1.xi, then a17 is equal to

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