WBJEE 2019 Physics Solved Paper

According to the question, we can draw the following diagramHere, T is the tension in the string.
In equilibrium condition,
‌ For mass ‌m1,T−m1g=m1a......(i)
‌ For mass ‌m2,m2g−T=m2a......(ii)
After adding Eqs. (i) and (ii), we get
m2g−m1g=m1a+m2a
(m2−m1)g‌‌=(m1+m2)a
a=

(m2−m1)

(m1+m2)

g