WBJEE 2019 Physics Solved Paper

The given circuit shows a balanced Wheatstone bridge. Now, the circuit becomesIn the branch AB, both capacitor are arranged in the series combination. Hence, its equivalent capacitance is given by
‌

1

CAB

=‌

1

20

+‌

1

20

=‌

2

20

=‌

1

10

CAB=10µF
Similarly, in branch CD.
CCD=10µF
Now, CAB and CCD are connected in parallel combination. Hence, the equivalent capacitance of the circuit,
Ceq=10+10=20µF
We know that, charge Q=CeqV
Q=20×10−6×150V
Amount of charge stored Q=3×10−3C