A straight line through the point (3, –2) is inclined at an angle 60° to the line \sqrt3 x + y = 1. If it intersects the X-axis, then its equation will be

Correct Answer is : y – x√3 + 2 + 3 √3 = 0

y + x \sqrt3 + 2 + 3 \sqrt3 = 0

y – x\sqrt3 + 2 + 3 \sqrt3 = 0

y – x\sqrt3 – 2 – 2\sqrt3 = 0

x – x \sqrt3 + 2 – 3 \sqrt3 = 0

WBJEE 2019 Math Solved Paper

Question : 43 of 75

Marks: +1, -0

A straight line through the point (3, –2) is inclined at an angle 60° to the line √3 x + y = 1. If it intersects the X-axis, then its equation will be

y + x √3 + 2 + 3 √3 = 0
y – x√3 + 2 + 3 √3 = 0
y – x√3 – 2 – 2√3 = 0
x – x √3 + 2 – 3 √3 = 0

Validate

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