Consider the function y = {\log}_4 (x+\sqrt{x^2+1}), a > 0, a ≠ 1. The inverse of the function

Correct Answer is : is x = sinh (y In a)

is x={\log}_{1{/}8} (y+\sqrt{y^2+1})

is x = \cosh (-y \, In \, 1/{a})

is x={\log}_{1{/}8} (y+\sqrt{y^2+1})

is x = \cosh (-y \, In \, 1/{a})

WBJEE 2018 Math Solved Paper

Question : 70 of 75

Marks: +1, -0

Consider the function y = log4(x+√x2+1), a > 0, a ≠ 1. The inverse of the function

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