WBJEE 2017 Chemistry Solved Paper

PbCl2(s)+Cl− →[PbCl]−(aq)
PbCl2(s)+2Cl− →[PbCl4]2−(aq)
Addition of chloride ions to a suspension of PbCl2 gives rise to soluble complex ion. In these reactions the additional chlorides break up the chloride bridgesthatcomprise the polymeric framework of solid PbCl2 (s)