WBJEE 2016 Physics Solved Paper

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Question : 38 of 40

Marks: +1, -0

The distance between a light source and photoelectric cell is d. If the distance is decreased to d/2 then

The emission of electron per second will be four times
Maximum kinetic energy of photoelectrons will be four times
Stopping potential will remain same
The emission of electrons per second will be doubled

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