WBJEE 2016 Math Solved Paper

f'(x) = (x−1)2 (4 - x)

The sign scheme of f'(x)
so clearly f(x) is increasing in (0, 3) as f'(x) ≥ 0. (B)
x = 4 is a critical point as f'(4) = 0. (C)
from f'(x), we can’t determine f(x) uniquely so f(0) can’t be predicted