WBJEE 2016 Math Solved Paper

Let (t, –t –1) be a parametric point of the line x + y+ 1 = 0
Distance of (t, –t –1) from 3x + 4y + 2 = 0 is

|3t+4(−t−1)+2|

√32+42

=

1

5

⇒ | -t - 2 | = 1 ⇒ | t + 2 | = 1, so t = -1 or t = -3
possible co-ordinates are (–1, 0) & (–3, 2)