General solution of y\frac{dy}{dx} + by^2 = a cos x, 0

Correct Answer is : (4b2 + 1) y2 = 2a (sinx + 2bcosx) + ce−2bx

y^2 = 2a(2b sinx + cosx) + ce^{-2bx}

(4b^2 + 1) y^2 = 2a (sinx + 2bcosx) + ce^{-2bx}

(4b^2 + 1) y^2 = 2a (sinx + 2bcosx) + ce^{2bx}

y^2 = 2a(2b sinx + cosx) - ce^{-2bx}

WBJEE 2016 Math Solved Paper

Question : 56 of 75

Marks: +1, -0

General solution of y

+by2 = a cos x, 0 < x < 1
Here c is any arbitrary constant

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