WBJEE 2015 Chemistry Solved Paper

2SO2 (g) + O2 (g) ⇌ 2SO3 (g) at 300K, the value of ΔG0 = – 690.9R T = 300 K
ΔG° = -RT ln K
or, – 690.9 R = – R × 300 × ln K
or, ln K =

690.9

300

= 2.303
K = 101 = 10
Unit of K
K = (atm)Δn
= (atm)2−3
= atm−1
∴ K = 10 atm−1