WBJEE 2014 Maths Solved Paper

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Question : 75 of 80

Marks: +1, -0

The solution of the differential equation

dy

dx

+

y

xlogex

=

1

x

under the condition y = 1 when x = e is

2y = logex +
1
logex
y = logex +
2
logex
ylogex = logex + 1
y = logex + e

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