WBJEE 2014 Maths Solved Paper

1 + z + z3+z4 = 0 ,
⇒ (1 + z) (1 + z3) = 0 , z = -1, -1, -ω, −ω2,
where ω is a cube root of unity, so, distinct roots are :
(-1, 0), (

1

2

,

√3

2

) , (

1

2

,−

√3

2

).
Distance between each of them is √3 . So, they form an equilateral triangle