The two half cell reactions of an electrochemical cell is given as Ag^{\+} + e^{-} → Ag ; E^\circ_{Ag+/Ag} = -0.3995 V Fe^{\++} + Fe^{\+++} + e^{-} ; E^\circ_{Fe^{\+++} \/ Fe^{\++}} = -0.7120 V

WBJEE 2014 Chemistry Solved Paper

Question : 44 of 60

Marks: +1, -0

The two half cell reactions of an electrochemical cell is given as
Ag+ + e− → Ag ; E°Ag+/Ag = -0.3995 V
Fe++ + Fe+++ + e− ; E°Fe+++∕Fe++ = -0.7120 V

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