WBJEE 2013 Math Solved Paper

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Question : 16 of 80

Marks: +1, -0

The value of the determinant

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1+a2−b2	2ab	−2b
2ab	1−a2+b2	2a
2b	−2a	1−a2−b2

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is equal to

0
(1+a2+b2)
(1+a2+b2)2
(1+a2+b2)3

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