f(x)=\frac{\log (\pi+x)}{\log (e+x)} is

Correct Answer is : decreasing in [0,∞)

decreasing in [0, \frac{\pi}{ {\e}}] and increasing in [\frac{\pi}{e}, \infty)

increasing in [0, \frac{\pi}{ {\e}}] and decreasing in [\frac{\pi}{e}, \infty)