Let f(x)={\\begin{array}{cc}3-x & \\\\text{ if }\\ & x&lt\ -3 \ 6 & \\\\text{ if }\\ & -3 \leq x \leq 3 . \\\\text{ Let }\\ \alpha \\\\text{ be the number }\\ \ 3+x & \\\\text{ if }\\ & x&gt\\3\end{array}. of points of discontinuity of f and \beta be the number of points where f is not differentiable. Then \alpha+\beta=

VITEEE 2024 Paper

Question : 75 of 125

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Let f(x)={

. of points of discontinuity of f and β be the number of points where f is not differentiable. Then α+β=

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