VITEEE 2023 Paper

Section: Physics

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Question : 7 of 125

Marks: +1, -0

The potential energy of a particle (Ux) executing S.H.M. is given by

Ux=‌
k
2
(x−a)2
Ux=k1x+k2x2+k3x3
Ux=Ae−bx
Ux=a constant

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