The sum of the first n terms of the series 1^2+2.2^2+3^2+2.4^2+5^2+2.6^2+. . . is \frac{n(n+1)^2}{2} when n is even. When n is odd the sum is

VITEEE 2022 Paper

Section: Mathematics

Question : 99 of 125

Marks: +1, -0

The sum of the first n terms of the series
12+2.22+32+2.42+52+2.62+...
is ‌

n(n+1)2

when n is even. When n is odd the sum is

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