VITEEE 2022 Paper

Section: Mathematics
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Question : 93 of 125
 
Marks: +1, -0
If the system of linear equations
x+ky+3z=0
3x+ky−2z=0
2x+4y−3z=0
has a non-zero solution (x,y,z), then ‌
xz
y2
is equal to :
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