The equation of the hyperbola with vertices at (0, \pm 6) and e=\frac{5}{3} is

Correct Answer is : y236−x264=1

\frac{x^2}{36}-\frac{y^2}{64}=1

\frac{y^2}{36}-\frac{x^2}{64}=1

\frac{x^2}{64}-\frac{y^2}{36}=1

\frac{y^2}{64}-\frac{x^2}{36}=1

VITEEE 2022 Paper

Section: Mathematics

Question : 104 of 125

Marks: +1, -0

The equation of the hyperbola with vertices at (0,±6) and e=‌

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