If \overrightarrow{\a}=2 \stackrel{\^}{\i}-2 \stackrel{\^}{\j}+\stackrel{\^}{\k} and \overrightarrow{\c}=-\stackrel{\^}{i}+2 \stackrel{\^}{\k} then {|{\c}|}^{\to} . \overrightarrow{\a} is equal to :

Correct Answer is : 2√5^i−2√5^j+√5^k

2 \\sqrt{5} \stackrel{\^}{i}+2 \\sqrt{5} \stackrel{\^}{j}+\\sqrt{5} \stackrel{\^}{k}

2 \\sqrt{5} \stackrel{\^}{i}-2 \\sqrt{5} \stackrel{\^}{j}+\\sqrt{5} \stackrel{\^}{k}

\\sqrt{5} \stackrel{\^}{i}+\\sqrt{5} \stackrel{\^}{j}+\\sqrt{5} {k^{\^}}

\\sqrt{5} \stackrel{\^}{i}+2 \\sqrt{5} \stackrel{\^}{j}+\\sqrt{5} \stackrel{\^}{k}

VITEEE 2021 Paper

Section: Mathematics

Question : 57 of 80

Marks: +1, -0

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−2

and

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=−

then

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|c|

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is equal to :

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