For the reaction N_2 + 3H_2 \to 2NH_3 if \frac{\\Delta[NH_3]}{\\Deltat}=2\times10^{-4}\mol\l^{-1}\s^{-1}, then value of \frac{\\Delta[H_2]}{\\Deltat} would be

Correct Answer is : 3×10−4moll−1s−1

1\times10^{-4}\mol\l^{-1}\s^{-1}

3\times10^{-4}\mol\l^{-1}\s^{-1}

4\times10^{-4}\mol\l^{-1}\s^{-1}

6\times10^{-4}\mol\l^{-1}\s^{-1}

VITEEE 2019 Paper

Section: Chemistry

Question : 45 of 125

Marks: +1, -0

For the reaction N2+3H2→2NH3
if

Δ[NH3]

Δt

=2×10−4‌mol‌l−1‌s−1, then value of

Δ[H2]

Δt

would be

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