VITEEE 2019 Paper

Section: Mathematics

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Question : 112 of 125

Marks: +1, -0

The solution of the differential equation

{1+x√(x2+y2)}dx+{√(x2+y2)−1}ydy=0

is

x2+
y2
2
+
1
3
(x2+y2)
3
2
=C
x2−
y2
3
+
1
2
(x2+y2)
1
2
=C
x−
y2
2
+
1
3
(x2+y2)
3
2
=C
None of these

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