VITEEE 2018 Paper

Acetophenone is a chemical compound having molecular formula C6H5

O ||

C

CH3.
It is a linear structure but if we talk about benzophenone it is a chemical compound having molecular formula (C6H5)2CO.
It has two benzene rings. In the above given tests, the test which is used to distinguish acetophenone and benzophenone is I2 and NaOH.
On reacting with acetophenone, iodine molecules react with methyl groups and form methyl iodide.
Due to the formation of methyl iodide it leads to the formation of yellow precipitate and it shows the compound is acetophenone.
But on the other hand, if I2 and NaOH reacts with benzophenone then it will not give any precipitate.
This reaction does not take place because benzophenone has a ring which does not lead any precipitate. Hence, option D is correct.