VITEEE 2018 Paper

I.E. =

Z2

n2

× 13.6 eV ... (i)
or

I1

I2

= Z−

12

n12

×

n22

Z22

... (ii)
Given I1 = - 19.6 × 10−18 , Z1 = 2
n1 = 1 , Z2 = 3 and n2 = 1
Substituting these values in equation (ii).
-

19.6×10−18

I2

=

4

1

×

1

9

or l2 = - 19.6 × 10−18 ×

9

4

= -4.41 x 10−17 J atom−1