VITEEE 2018 Paper

Rearranging the circuits, we get the following circuit

∴ equivalent capacitance between A and B
CAB =

4×4

4+4

= 2 µF
and equivalent capacitance between C and A
CCD =

8×8

8+8

= 4 µF
∴ Cab = 2 µF + 4 µF = 6 µF