VITEEE 2017 Paper

Here, centre is A (1,2), and Tangent at B (1,7) is
x . 1 + y . 7 (x + 1) - 2 (y + 7) - 20 = 0 or y = 7 ... (i)
Tangent at D (4,-2) is
3x - 4y - 20 = 0 ...(2)
Solving (1) and (2), we get C is (16,7)
Area ABCD = 2 (Area of Δ ABC)
= 2 ×

1

2

AB × BC
AB × BC = 5 × 15 = 75 units